Post-Level Test 2 Practice... Do you get these???

No. 1(a) 180 (2 S.F.)
No. 1(b) after evaluating, we'll get 29.853810... correcting to 1 SF, we get 30 (to 1 S.F.)

No. 2
Estimation:
538 x 0.053
≈ 500 x 0.05 (to 1 S.F.)
= 25
The value would be 28.514

No. 3
(a) The possible integers are 75, 76, 77, 78, 79, 81, 82, 83, 84
[Note that 80 is not included in the answer because it asked for integers that are rounded to... ]
(b) The prime numbers are 79, 83

No. 4
We will get 0.943309132... = 0.94 (to 2 decimal places)

No. 5
We will get 1.10845164... = 1.11 (correct to 3 S.F.)

No. 6
Answer: 7 ½

No. 7
Given that the breadth is (2x - 1) m
Height is twice its length, Height = 2(2x - 1)

(a) Perimeter = 2 x Length + 2 x Breadth
= 2 x 2(2x - 1) + 2 x (2x - 1)
= 4(2x - 1) + 4x - 2
= 8x - 4 + 4x - 2
= 12x - 6 m (shown)

(b) Area = Length x Breadth {Note: This is beyond chapter 4}
= 2(2x - 1) x (2x - 1)
= 2 [(2x-1)(2x) - (2x-1)(1)]
= 2 [4x² - 2x - 2x + 1]
= 2 [4x² - 4x + 1]
= 8x² - 8x + 2

No. 8
Note that the age given were "3 years ago"
(i) Given that, 3 years ago, Sam's age was x + 1
and Oreo's age was 1½ times as old as Sam
Oreo's age is therefore 1½ x (x + 1)
= 3/2 x (x + 1)
= 3x/2 + 3/2
alternatively, can be written as
= (3x + 3)/2

(ii) Oreo's present age
= 3x/2 + 3/2 + 3
= 3x/2 + 9/2
alternatively, can be written as
= (3x + 9)/2

(iii) Sum of Sam & Oreo's present age
= Sam's present age + Oreo's present age
= (x + 1 + 3) + 3x/2 + 9/2
= x + 4 + 3x/2 + 9/2
= 5x/2 + 17/2
alternatively, can be written as
= (5x + 17)/2

By the way, there's a piece of redundant information (i.e. the sum of their present ages is 86). This information only becomes useful if we need to find out the age of Oreo and Sam.